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Community Forums => The Lounge => Topic started by: RED-DOG on June 26, 2018, 01:59:50 PM



Title: Mathsy question
Post by: RED-DOG on June 26, 2018, 01:59:50 PM
If you lay a 5ft plank on on the floor, (No Celtic jokes please) and then raise one end 25 degrees, how hight from the floor will the raised end be?


Title: Re: Mathsy question
Post by: celtic on June 26, 2018, 02:09:28 PM
If you lay a 5ft plank on on the floor, (No Celtic jokes please) and then raise one end 25 degrees, how hight from the floor will the raised end be?


loool :)


Title: Re: Mathsy question
Post by: Longines on June 26, 2018, 02:36:28 PM
0.00320201383517491 furlongs.

yw.

http://www.g3asr.co.uk/calculators/triangle.htm



Title: Re: Mathsy question
Post by: RED-DOG on June 26, 2018, 03:19:14 PM
0.00320201383517491 furlongs.

yw.

http://www.g3asr.co.uk/calculators/triangle.htm




I can't see where to write 5ft plank.


Title: Re: Mathsy question
Post by: doubleup on June 26, 2018, 03:40:09 PM
it would be in the hypotenuse box but that isn't enough info as you need the bottom line of the triangle as well


Title: Re: Mathsy question
Post by: RED-DOG on June 26, 2018, 03:44:22 PM
it would be in the hypotenuse box but that isn't enough info as you need the bottom line of the triangle as well


Surely there is enough information in the original question though?


Title: Re: Mathsy question
Post by: doubleup on June 26, 2018, 03:53:24 PM
it would be in the hypotenuse box but that isn't enough info as you need the bottom line of the triangle as well


Surely there is enough information in the original question though?

don't you just have the length of one side and the angles? 


Title: Re: Mathsy question
Post by: RED-DOG on June 26, 2018, 04:12:11 PM
it would be in the hypotenuse box but that isn't enough info as you need the bottom line of the triangle as well


Surely there is enough information in the original question though?

don't you just have the length of one side and the angles? 


I'm going to make some roof trusses to support metal tiles. The recommended angle for metal tile installation is 25 degrees, so what I need to know is how high the apex needs to be (above gutter hight) to give me the correct angle assuming that each side of the roof, (or two sides of the triangle) are 5ft long.


Title: Re: Mathsy question
Post by: Longines on June 26, 2018, 04:16:31 PM
If you put 25 degrees in bottom angle and 60 (inches) in hypotenuse, you get 25.36" as the height and 54.38" as the base length.


Title: Re: Mathsy question
Post by: RED-DOG on June 26, 2018, 04:22:35 PM
If you put 25 degrees in bottom angle and 60 (inches) in hypotenuse, you get 25.36" as the height and 54.38" as the base length.


Yep, I can live with that.

 Thanks.


Title: Re: Mathsy question
Post by: doubleup on June 26, 2018, 04:59:25 PM
If you put 25 degrees in bottom angle and 60 (inches) in hypotenuse, you get 25.36" as the height and 54.38" as the base length.

hmmm I put in both the angles and got "computer says no"


Title: Re: Mathsy question
Post by: Longines on June 26, 2018, 05:41:57 PM
enter EITHER 2 sides OR 1 side & 1 angle

We didn't need your fancy error handling stuff 17 years ago, we had users that read the instructions  ;whistle;  ;snoopy'sguns;  :)up


Title: Re: Mathsy question
Post by: doubleup on June 26, 2018, 07:30:47 PM
for centuries man has got by without reading instructions until something has gone wrong, so I doubt this suddenly changed 17 years ago.  :)


Title: Re: Mathsy question
Post by: Rupert on June 28, 2018, 07:34:26 AM
cos theta = adj/hypotenuse

=> hypotenuse * sin theta = height
=> 5ft * sin 25(pi/180) = height
=> height = 2.11308989034ft


Title: Re: Mathsy question
Post by: RED-DOG on June 28, 2018, 08:16:15 AM
cos theta = adj/hypotenuse

=> hypotenuse * sin theta = height
=> 5ft * sin 25(pi/180) = height
=> height = 2.11308989034ft

Amazing.


Title: Re: Mathsy question
Post by: Tractor on June 28, 2018, 08:20:28 AM
cos theta = adj/hypotenuse

=> hypotenuse * sin theta = height
=> 5ft * sin 25(pi/180) = height
=> height = 2.11308989034ft

Incredible. I wish i could understand how you get to that.


Title: Re: Mathsy question
Post by: Rupert on June 28, 2018, 08:23:11 AM
http://www.bbc.co.uk/schools/gcsebitesize/maths/geometry/trigonometryrev1.shtml

GCSE maths

if you put calculator in degrees you don't need to convert to radians. Also top line was wrong formula, lol


Title: Re: Mathsy question
Post by: celtic on June 28, 2018, 08:29:14 AM
cos theta = adj/hypotenuse

=> hypotenuse * sin theta = height
=> 5ft * sin 25(pi/180) = height
=> height = 2.11308989034ft

I make it about the same.


Title: Re: Mathsy question
Post by: RED-DOG on June 28, 2018, 09:03:53 AM
cos theta = adj/hypotenuse

=> hypotenuse * sin theta = height
=> 5ft * sin 25(pi/180) = height
=> height = 2.11308989034ft

I make it about the same.


...and we're back to 5ft planks.


Title: Re: Mathsy question
Post by: booder on June 28, 2018, 09:53:01 AM
cos theta = adj/hypotenuse

=> hypotenuse * sin theta = height
=> 5ft * sin 25(pi/180) = height
=> height = 2.11308989034ft

I make it about the same.


...and we're back to 5ft planks.


Too easy Tom , too easy.


Title: Re: Mathsy question
Post by: RED-DOG on June 28, 2018, 12:57:47 PM
cos theta = adj/hypotenuse

=> hypotenuse * sin theta = height
=> 5ft * sin 25(pi/180) = height
=> height = 2.11308989034ft

I make it about the same.


...and we're back to 5ft planks.


Too easy Tom , too easy.

I know, I feel dirty now.

The closest I could get to working out 25 degrees of elevation was 4in up for every 12in of length.

So 5tft is 5x4in =25in.

If course, as I raise the plank it becomes shorter horizontally so it's just a rough estimate rather than an actual answerer.

I think I'll just lift it up until it looks right.


Title: Re: Mathsy question
Post by: EvilPie on June 28, 2018, 02:32:50 PM
cos theta = adj/hypotenuse

=> hypotenuse * sin theta = height
=> 5ft * sin 25(pi/180) = height
=> height = 2.11308989034ft

Can we, or I suppose the question is should we decimalise an imperial measurement?

2.113ft is pretty meaningless isn't it? Some people could easily mistake this for 2' 11" when it's actually about 2' 1 1/3"

Probably best to convert 5ft in to metric first which won't go down well but it'll give a far more accurate way of getting that vertical height.


Title: Re: Mathsy question
Post by: tikay on June 28, 2018, 04:05:59 PM
cos theta = adj/hypotenuse

=> hypotenuse * sin theta = height
=> 5ft * sin 25(pi/180) = height
=> height = 2.11308989034ft

I make it about the same.


...and we're back to 5ft planks.


Too easy Tom , too easy.

I know, I feel dirty now.

The closest I could get to working out 25 degrees of elevation was 4in up for every 12in of length.

So 5tft is 5x4in =25in.

If course, as I raise the plank it becomes shorter horizontally so it's just a rough estimate rather than an actual answerer.

I think I'll just lift it up until it looks right.

That was always going to be Tom's solution.....