blonde poker forum

I imagine a few have seen this before, but I hadn't until today and thought it was quite cool.

Three shooters, A, B, and C. Each has 1 bullet and they are going to take their shots sequentially in that order.

A has a 1/3 chance of hitting his target.
B has a 1/2 chance of hitting his target.
C has a 100% chance of hitting his target.

A goes first. Who should he shoot, and why?

They did this on QI, before anyone pretends they worked it out.

http://www.youtube.com/watch?v=qL8raEwtzVQ

Are we to assume that they are shooting at each other?

Yes, though with differing degrees of accuracy.

if they miss their intended target will they deffo hit one of the others?  If so he's got to aim at himself, surely?  seems far too obvious though so assuming that's wrong.

They did it in game theory a long time before they did it on QI

Farce! Correct answer wasn't offered as an option.

Surely A shoots B, as if A shoots C then its B to have a turn next and he shoots A.

Or did I misunderstand it?

but if he kills B then he's left with just C who will shoot him 100% of the time. not great odds for A

Yes it was... technically. What's your answer?

Well if he had to shoot at someone, (As the question implies) He would be better off shooting at himself.

Spoiler so in small
Supposing A shoots skywards, B shoots and misses, what does C do? Just chill and not get an attempted murder charge right?

If A shoots B, who does B then shoot when it is his turn if A has been successful?

No one, he's dead.

A has to shoot C and miss on purpose.
B then knows he has to shoot C because he knows that if he hits A then C will then take him out with his 100% accuracy.
C has to shoot B because as C is still alive it means B has missed his first shot and with a 50% success will hit his second shot at C if C takes out A.

A knows he will get 2 shots at B because if B hits C then he will miss his 2nd shot for his 50% record to be true. So A takes second shot at B knowing that B will miss his 2nd shot so gives A the third bullet to complete job with 3rd bullet and 33% success

If A or B take out each other with their first shot they are dead from C's accuracy


Lol. They only got one bullet. Obv not seen this before either

correct, so the shooting sequence order has stopped at A, coz C doesnt fire if B doesnt fire?

pretty sure c will still get his turn and you've not allowed for the 2 times in 3 when a misses b

we don't have enough info in op really but if we're assuming that b and c will always fire at one of the others and that their choice of target is random rather than revenge or game theory based then a is def better off shooting into the air. back of a fag packet calculations give me a 50% death rate for that, a 66% death rate if he shoots at b and some other number if he shoots at c, I got bored at this point

It is always best for A to intentionally miss. By doing so B is forced to shoot C. For B to shoot and kill A at this point would be stupid as C will then shoot him with 100% accuracy. If B successfully shoots C then it ends with A and B alive. If B misses then C will shoot either A or B at random - but this is still better than A shooting and killing and being aimed at with certainty.

If we assume they all have infinite bullets, and continue shooting in the order A, B, C, it still works. If B and C are alive then A should intentionally miss. By doing so he ensures he will always have the first shot when it becomes a duel.

Always find these thing tedious. Why does anyone have to shoot anyone?

PEACE!

George is sat playing the scoop. He just posted on facebook die stars and his fairy god mother hears him. He is allowed to shoot the guy who donked him out or the CEO of Pokerstars. Who does he shoot?

Lederer obv