Right, i used an icm to do this.
Pos Payout Additional %
1st 1206 927 60%
2nd 728 449 29%
3rd 402 123 8%
4th 324 45 3%
5th 279 0 0%
From the original question the chips counts are
Person Chips Equity
LS 659039 0.2356
Bert 502486 0.1917
Dan 896661 0.2926
WPT 690678 0.2439
POP 83136 0.0362
If the 9-9 folds
Person Chips Equity
LS 759239 0.2631
Bert 396286 0.1602
Dan 895661 0.2945
WPT 689678 0.2456
POP 82136 0.0366
If the 9-9 loses
Person Chips Equity
LS 1158525 0.3620
Bert 0 0.0
Dan 895661 0.3121
WPT 689678 0.2640
POP 82136 0.0619
If the 9-9 wins
Person Chips Equity
LS 156553 0.0779
Bert 1007972 0.3251
Dan 895661 0.3020
WPT 689678 0.2533
POP 82136 0.0417
Soooooooooooooooooo
(that's the closest emoticon to a drumroll we have)
If P is the probability of winning the hand,
0.3251* P + (1 - P) * 0.0 > 0.1602
Gives P as 49.2% which means that the 9-9 should call if it has more than a 49.2% chance of winning the hand. Pokerstove gives this hand range as 77+,A9s+,KTs+,QTs+,JTs,ATo+,KJo+ and equates to the top 12.5% of hands. Now, because he is obviously doing it with a larger range than that the 9-9 should call. (it was luck boldie
)
ps, can someone check these pls cos i've probably made a mistake somewhere.
Ok, so now a new question. How do you play the A-3 in that position and with those stack sizes.