no no no
in both examples of mine, the same amount of water is displaced
the volume of the cube in the water is 10x10x9
therefore the volume displaced by the cube is always going to be 10x10x9
that volume will not change no matter how big the bath is provided that bath itself is larger than 10x10x9
no substitue the cube for celtic, and change the shape of the bah from a cube to a "celtic" and you will see that i am right
it's not about how much water is still in the bath, its about how much water the item, ie celtic, displaces, if there is still water in the bath and the "celtic" is not touching any surfaces, then he is floating
So what if you take your 11 x 11 x 10 bath and only half fill it with water meaning that there's only 605cm cubed available to be displaced.
Will your 10x10x10 float now that there isn't 900cm cubed available to be displaced in the first place?
imagine that the bath of 11x11x10 is a complete cube, in effect it is open topped, but imagine it as a cube
the volume of that cube would be 1210 cubic cm
if you put in 605 cubic cm of water, the other part of that, the volume above the water, would be 605 cubic cm of air
as you start to lower the 10x10x10 cube into the bath you start to displace the air, then when the cube touches the water and starts to lower into it, the water level appears to rise, but until the water reaches the top the volume of water in the bath is still the same, the only thing changing is that there is more "cube" and less air.
once the water starts to overflow, there is no more air left to displace, and it is water being displaced instead
eventually the cube will no longer go any lower in the water, and will, in our example, have 1cm above the water level (10x10x1 cubic cm)
does that make sense now?
i'm not a teacher, btw, so it could well be my explanation that is lacking