Question

[Cf]

lol, good answer. but no. i can assure you the other side is a tails

[Cf]

oh ffs. i got to the end of page 34 and found it continues in another 17 page thread.

[Cf]

Not reading anymore of it but I did find this absolute gem. They emailed camelot asking about it. This was the response...

Originally Posted by Camelot
Thank you for your email dated 15 July 2010.

As stated the odds of matching all six numbers are 1 in 13,983,816. These odds apply for each individual ticket purchased.

Should you purchase two tickets with different sets of numbers, this does not halve your chances of winning the lottery, it reduces the probability by 1. The number of tickets you purchase does not act as a denominator against the total odds, it reduces the total probability by that amount.

For example, if you purchased 100 tickets, the odds of one of those tickets winning would not become 1 in 139,838 it becomes 1:13,983,716.

With a dice role, any particular number can be rolled again. With the Lotto, there is a maximum number of combinations of 13,983,816 and once one combination is removed by buying a ticket, that combination cannot be produced again therefore it is minus 1.

Therefore odds of one ticket = 1:13,983,816
" odds of two tickets= 1:13,983,815

By purchasing two tickets you do of course have two chances of winning although i hope you can see the odds are not halved.

[CHIPPYMAN]

 

[dagarbisa]

I would guess 2,652/1 but I am always wrong on these odd thingies.

yes, You have mistaken but by the time you will learn it. This is pure mathematics(Probability)

it would be 52C2 x 51C1 as in 1326. 1/26 of getting 1 or 1/51 of getting second card in 1326.

[kinboshi]

Just caught up on this thread.