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Author Topic: What are the odds....  (Read 2423 times)
pleno1
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« on: January 17, 2011, 05:31:44 PM »

of getting a 7 card straight?
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celtic
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« Reply #1 on: January 17, 2011, 05:32:39 PM »

err 0%?
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Cf
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« Reply #2 on: January 17, 2011, 06:03:20 PM »

err 0%?

this
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EvilPie
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« Reply #3 on: January 17, 2011, 06:03:37 PM »

If you mean being dealt a 7 card straight in a 7 card game it's a bit tough to calculate.

Your first card doesn't matter. You just get dealt it. You then need 6 specific cards to complete the straight but there are 4 of each.

So the chances against your second card being one of your straigting cards is 24/51

The next card is 20/50

Next 16/49

Next 12/48

Next 8/47

And finally 4/46 to complete the straight.

So if you multiply these together you'll get your answer I think.

(24*20*16*12*8*4) / (51*50*49*48*47*46)

= 2949120 / 12966811200

= 0.000227436

Or about 4397 to 1


Maybe........
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doubleup
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« Reply #4 on: January 17, 2011, 06:20:16 PM »

err 0%?

obv there isnt such a thing in poker but if there was it would be calculated dividing 4^7 by the possible 7 card cominations from 52 cards.

oops edit there are 8 poss 7 cards str8s so 4^7 *8

about 1000-1 according to excel

btw evilpies mistake is that some of his str8s can only be continued/completed with one card.

« Last Edit: January 17, 2011, 06:42:09 PM by doubleup » Logged
outragous76
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« Reply #5 on: January 17, 2011, 07:29:56 PM »

err 0%?

obv there isnt such a thing in poker but if there was it would be calculated dividing 4^7 by the possible 7 card cominations from 52 cards.

oops edit there are 8 poss 7 cards str8s so 4^7 *8

about 1000-1 according to excel

btw evilpies mistake is that some of his str8s can only be continued/completed with one card.



and if you are dealt an A as first card straights become a little more tricky
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EvilPie
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« Reply #6 on: January 17, 2011, 07:41:49 PM »

err 0%?

obv there isnt such a thing in poker but if there was it would be calculated dividing 4^7 by the possible 7 card cominations from 52 cards.

oops edit there are 8 poss 7 cards str8s so 4^7 *8

about 1000-1 according to excel

btw evilpies mistake is that some of his str8s can only be continued/completed with one card.



and if you are dealt an A as first card straights become a little more tricky

I thought this but then changed my mind. I think A is actually a good card because it's actually smack in the middle of the deck. It's as good as an 8 for allowing you to continue after your 2nd card.

It all depends on your 2nd card really. And the odds against your second card giving you a chance to continue are based on what your first card is.

Does this mean that you can't actually calculate the true odds because it changes depending on what order the cards get dealt in?

Phew... Tough one....
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pleno1
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« Reply #7 on: January 17, 2011, 07:44:52 PM »

i have 56, flop comes 789, turn 10, river 11.
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« Reply #8 on: January 17, 2011, 07:55:17 PM »

err 0%?

obv there isnt such a thing in poker but if there was it would be calculated dividing 4^7 by the possible 7 card cominations from 52 cards.

oops edit there are 8 poss 7 cards str8s so 4^7 *8

about 1000-1 according to excel

btw evilpies mistake is that some of his str8s can only be continued/completed with one card.



and if you are dealt an A as first card straights become a little more tricky

I thought this but then changed my mind. I think A is actually a good card because it's actually smack in the middle of the deck. It's as good as an 8 for allowing you to continue after your 2nd card.

It all depends on your 2nd card really. And the odds against your second card giving you a chance to continue are based on what your first card is.

Does this mean that you can't actually calculate the true odds because it changes depending on what order the cards get dealt in?

Phew... Tough one....

An ace isn't as good as an 8 since there are only two straights that contain an ace - there is no 32AKQJT seven card straight.

As stated above it's about 1000/1 (1019.7/1 to be more precise, I think).
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« Reply #9 on: January 17, 2011, 08:02:58 PM »

Ok. Pretty sure i've got it right here...

Let's assume we're just playing draw poker using 7 card hands. We select 7 cards.

There are 8 possible straights...

A..7
..
8..A

So there are 32 possible straight flushes.

For the total number of straights we do...

8C1 (the 8 straights) x (4C1)^7 (the suit combinations) = 131,072 possible straights

Remove the straight flushes gives us 131,040 straight combinations.

There are 52C7 = 133784560 possible 7 card hands.

So the chance of drawing a straight is: 0.098%
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doubleup
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« Reply #10 on: January 17, 2011, 08:10:38 PM »

Ok. Pretty sure i've got it right here...

Let's assume we're just playing draw poker using 7 card hands. We select 7 cards.

There are 8 possible straights...

A..7
..
8..A

So there are 32 possible straight flushes.

For the total number of straights we do...

8C1 (the 8 straights) x (4C1)^7 (the suit combinations) = 131,072 possible straights

Remove the straight flushes gives us 131,040 straight combinations.

There are 52C7 = 133784560 possible 7 card hands.

So the chance of drawing a straight is: 0.098%

If you are going to be that pedantic you should remove the 7 card str8s that are 5 card flushes  Wink

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pokerfan
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« Reply #11 on: January 17, 2011, 08:13:28 PM »

i have 56, flop comes 789, turn 10, river 11.
101:1 to flop 789, then depends if you want exactly a 10 on turn or a 10 or j. Someone do the math for both  pls.
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« Reply #12 on: January 17, 2011, 08:15:11 PM »

Ok. Pretty sure i've got it right here...

Let's assume we're just playing draw poker using 7 card hands. We select 7 cards.

There are 8 possible straights...

A..7
..
8..A

So there are 32 possible straight flushes.

For the total number of straights we do...

8C1 (the 8 straights) x (4C1)^7 (the suit combinations) = 131,072 possible straights

Remove the straight flushes gives us 131,040 straight combinations.

There are 52C7 = 133784560 possible 7 card hands.

So the chance of drawing a straight is: 0.098%

If you are going to be that pedantic you should remove the 7 card str8s that are 5 card flushes  Wink



Why? I'm just assuming 7 card hands Smiley
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doubleup
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« Reply #13 on: January 17, 2011, 09:15:32 PM »

Ok. Pretty sure i've got it right here...

Let's assume we're just playing draw poker using 7 card hands. We select 7 cards.

There are 8 possible straights...

A..7
..
8..A

So there are 32 possible straight flushes.

For the total number of straights we do...

8C1 (the 8 straights) x (4C1)^7 (the suit combinations) = 131,072 possible straights

Remove the straight flushes gives us 131,040 straight combinations.

There are 52C7 = 133784560 possible 7 card hands.

So the chance of drawing a straight is: 0.098%

If you are going to be that pedantic you should remove the 7 card str8s that are 5 card flushes  Wink



Why? I'm just assuming 7 card hands Smiley

in the voice of "this one goes up to eleven"

a straight flush is a straight and a flush

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kinboshi
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« Reply #14 on: January 17, 2011, 09:23:55 PM »

Disappointed. No one's gone for the 50/50 option.
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