I don't think they're equally likely, there is only one way to make zero and a loads and loads, to use a techincal term, to make 182.
Presumably that doesn't matter, as the distribution of scores will be a normal curve around the 182-point, no..? So the 182s will be balanced out by 181s, 183s etc, which aren't divisble by 13.
Isn't the problem with this that there's a chance of getting 0. So there are 365 possible scores, not 364. Playing to 13, there's a 1 in 4503599627370496 chance of getting 0. (I just did it, but the floor's a right mess now).
So actually the chance of the score being divisible by 13 is marginally less than 1 in 13. But the discrepancy will be higher the lower down you go. Do it with just one ace - the chance of the score being divisble by 1 isn't 1 in 1, cos now there's a 50% chance of the score being 0.