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Help!
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Topic: Help! (Read 4469 times)
tikay
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Help!
«
on:
June 30, 2007, 12:18:44 AM »
I need to answer an awkward question for a column I do elsewhere.
On a (full) 6 seater table,what are the odds of 4 players being dealt Pocket Pairs?
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efcfan
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Re: Help!
«
Reply #1 on:
June 30, 2007, 12:29:21 AM »
I'll have a stab at about 50,000 to 1.
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MKKfish
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Re: Help!
«
Reply #2 on:
June 30, 2007, 12:46:51 AM »
I may be being amazingly thick here but surely it's the same as any other distribution of any pre-flop four hands at a six seater...
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tikay
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Re: Help!
«
Reply #3 on:
June 30, 2007, 12:48:40 AM »
Quote from: MKKfish on June 30, 2007, 12:46:51 AM
I may be being amazingly thick here but surely it's the same as any other distribution of any pre-flop four hands at a six seater...
...which is.......?
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tikay
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Re: Help!
«
Reply #4 on:
June 30, 2007, 12:50:48 AM »
I am sure I'm wrong here, but if the chance of being dealt a PP is, say, 16/1, then is the answer 16x16x16x16? Then again, how would that differ - if at all - from a full table of 9 or 10?
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MKKfish
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Re: Help!
«
Reply #5 on:
June 30, 2007, 12:51:12 AM »
...which is.......?
Lots
Well I'm just back from the pub but.....progessive distribution of (oh feck lets just deal with 4 hands), would be
2/52 * 2/50 * 2/48 * 2/46...again I'm not sure but I think the pairs bit clouds the question.
«
Last Edit: June 30, 2007, 12:54:45 AM by MKKfish
»
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tikay
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Re: Help!
«
Reply #6 on:
June 30, 2007, 12:53:00 AM »
Quote from: MKKfish on June 30, 2007, 12:51:12 AM
...which is.......?
Lots
That's what I thought. What you reckon, a shed-load to 1?
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efcfan
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Re: Help!
«
Reply #7 on:
June 30, 2007, 12:54:46 AM »
After the dealer has dealt the first 6 cards, there are 46 left in the pack and only 3 of them will pair you up, so about 15 to 1.
So four to pair up is roughly 15x15x15x14 ?
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tikay
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Re: Help!
«
Reply #8 on:
June 30, 2007, 12:57:21 AM »
Quote from: efcfan on June 30, 2007, 12:54:46 AM
After the dealer has dealt the first 6 cards, there are 46 left in the pack and only 3 of them will pair you up, so about 15 to 1.
So four to pair up is roughly 15x15x15x14 ?
Thanks Mate.
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MKKfish
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Re: Help!
«
Reply #9 on:
June 30, 2007, 12:57:35 AM »
Tikay,
I do think the pairs bit is irrelevant in establishing the odd. James, however, would argue that it is -EVament unless you had position as well.
Cheers,
FishMKK
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byronkincaid
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Re: Help!
«
Reply #10 on:
June 30, 2007, 12:58:24 AM »
I'm really bad at maths so I don't even know why I'm posting this but if 16/1 is roughly 6% then is it not
.06*.06*.06*.06*100 = 0.001296%
but I can't work out the 6 people v 10 people thing. The odds must be better that it will happen at a 10 seat table right
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tikay
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Re: Help!
«
Reply #11 on:
June 30, 2007, 12:59:20 AM »
My head hurts.
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MKKfish
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Re: Help!
«
Reply #12 on:
June 30, 2007, 01:00:05 AM »
Yeah - I think the Eastbourne FC fan is right..
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booder
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Lazy , Hazy days
Re: Help!
«
Reply #13 on:
June 30, 2007, 01:01:11 AM »
even money on crypto
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Quote from: action man
im not speculating, either, but id have been pretty peeved if i missed the thread and i ended up getting clipped, kindly accepting a lift home.
In the end, we will remember not the words of our enemies, but the silence of our friends.
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RED-DOG
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Re: Help!
«
Reply #14 on:
June 30, 2007, 01:03:31 AM »
It's about evens on the Sky Poker Open.
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The older I get, the better I was.
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