ICHUC 4 Nations Betting

[North Angel]

You will find the below odds at vcbet.com


England  7/4   
Ireland  2/1   
Wales  9/4   
Scotland  4/1


Dave Masters (Ireland)  9/1   
Paul Foltyn (England)  10/1   
Dave O`Callaghan (Ireland)  10/1   
Niall O`Callaghan (Ireland)  10/1   
Martin Cavanagh (Wales)  10/1   
James Dempsey (England  12/1   
Richard Ruddling Smith (Wales)  12/1   
Jen Mason (England)  12/1   
Rick Trigg (England)  12/1   
Carl Thomas (Wales)  12/1   
Paul Reast (England)  12/1   
Rob Taylor (Ireland)  14/1   
Kevin Conway (England)  14/1   
Mike Lacey (Ireland)  14/1   
Phil Wise (Wales)  20/1   
Chris Forde (Wales)  20/1   
Dave Baker (England)  20/1   
Emma Strutt (Wales)  25/1   
Thomas Stott (Scotland)  25/1   
Matthew Stevens (Wales)  25/1   
Alistair Fowler (Scotland)  25/1   
Rod Copeland (Scotland)  33/1   
Stephen Donnelly (Scotland)  33/1   
Mark McKenzie (Scotland)  33/1   
Colette Murphy (Ireland)  33/1   
Stephen Masterton (Scotland)  40/1   
Gary Watters (England)  40/1   
Billy Mcalistar(Scotland)  40/1   
Wayne Nash (Wales)  40/1   
Ken Doherty (Ireland)  50/1   
Cairn Rennie (Scotland)  125/1

[Ironside]

when is the draw being made?

i cant back somone eachway unless i know they can make the final with me

[North Angel]

The Draw will be made friday evening in front of a live audience 

[Ironside]

why not do it infront of a dead audience?

[North Angel]

why not do it infront of a dead audience?

Because the Scottish team wont be arriving til Saturday (Davey told me to say it......Honest!)

Ang x x

[Ironside]

tell davey if he waits till after we arrive he can conduct it dead LOL

[thetank]

Just a bit of musing here.......forgive me if I'm stating the obvious.

Assuming odds were given on a similarly structured coin toss contest. The odds of everyone winning each match would be 50%, the true price of all the competitors would be 31 to 1.

The true odds of getting past the first round = evens
The true odds of getting past the second round = 3 to 1
The true odds of getting past their quarter final = 7 to 1
The true odds of getting past their semi final = 15 to 1
The true odds of being coin toss champ 2006 = 31 to 1

The true price of an each way bet (that pays out if they win or come second) would be 15 to 1. (My mum was on 15 to 1 once, but that's another story)


Back to the poker tournament, where skill is involved too, and let's assume you're betting on an underdog to the field. Furthermore, let's assume for this model that they have a 33.33% chance of winning each match.

The true odds of getting past the first round = 2 to 1
The true odds of getting past the second round = 8 to 1
The true odds of getting past their quarter final = 26 to 1
The true odds of getting past their semi final = 80 to 1  EACH WAY BET PAYS
The true odds of winning the whole jim-bosch = 242 to 1  TO WIN BET PAYS


Say you are priced at 225 to 1, an each way bet that pays out at half the odds. (So 112 to 1)

You see what happens here. We can get 225 to 1 on a 242 to 1 shot, bad value.

but...

We can get 112 to 1 on an 80 to 1 shot, decent value.




Without going into further mathmatical musings, I'll simply offer this hyopthesis.

For the most value....
If someone you like is priced at below 31/1, bet them to win.
If someone you like is priced above 31/1, bet them E/W.

Makes sense to me. A favourite in the final match loses value when the odds are halved for the E/W, while an underdog gains.

[Royal Flush]

Just a bit of musing here.......forgive me if I'm stating the obvious.

Assuming odds were given on a similarly structured coin toss contest. The odds of everyone winning each match would be 50%, the true price of all the competitors would be 31 to 1.

The true odds of getting past the first round = evens
The true odds of getting past the second round = 3 to 1
The true odds of getting past their quarter final = 7 to 1
The true odds of getting past their semi final = 15 to 1
The true odds of being coin toss champ 2006 = 31 to 1

The true price of an each way bet (that pays out if they win or come second) would be 15 to 1. (My mum was on 15 to 1 once, but that's another story)


Back to the poker tournament, where skill is involved too, and let's assume you're betting on an underdog to the field. Furthermore, let's assume for this model that they have a 33.33% chance of winning each match.

The true odds of getting past the first round = 2 to 1
The true odds of getting past the second round = 8 to 1
The true odds of getting past their quarter final = 26 to 1
The true odds of getting past their semi final = 80 to 1  EACH WAY BET PAYS
The true odds of winning the whole jim-bosch = 242 to 1  TO WIN BET PAYS


Say you are priced at 225 to 1, an each way bet that pays out at half the odds. (So 112 to 1)

You see what happens here. We can get 225 to 1 on a 242 to 1 shot, bad value.

but...

We can get 112 to 1 on an 80 to 1 shot, decent value.




Without going into further mathmatical musings, I'll simply offer this hyopthesis.

For the most value....
If someone you like is priced at below 31/1, bet them to win.
If someone you like is priced above 31/1, bet them E/W.

Makes sense to me. A favourite in the final match loses value when the odds are halved for the E/W, while an underdog gains.

get a job

[NoflopsHomer]

Just a bit of musing here.......forgive me if I'm stating the obvious.

Assuming odds were given on a similarly structured coin toss contest. The odds of everyone winning each match would be 50%, the true price of all the competitors would be 31 to 1.

The true odds of getting past the first round = evens
The true odds of getting past the second round = 3 to 1
The true odds of getting past their quarter final = 7 to 1
The true odds of getting past their semi final = 15 to 1
The true odds of being coin toss champ 2006 = 31 to 1

The true price of an each way bet (that pays out if they win or come second) would be 15 to 1. (My mum was on 15 to 1 once, but that's another story)


Back to the poker tournament, where skill is involved too, and let's assume you're betting on an underdog to the field. Furthermore, let's assume for this model that they have a 33.33% chance of winning each match.

The true odds of getting past the first round = 2 to 1
The true odds of getting past the second round = 8 to 1
The true odds of getting past their quarter final = 26 to 1
The true odds of getting past their semi final = 80 to 1  EACH WAY BET PAYS
The true odds of winning the whole jim-bosch = 242 to 1  TO WIN BET PAYS


Say you are priced at 225 to 1, an each way bet that pays out at half the odds. (So 112 to 1)

You see what happens here. We can get 225 to 1 on a 242 to 1 shot, bad value.

but...

We can get 112 to 1 on an 80 to 1 shot, decent value.




Without going into further mathmatical musings, I'll simply offer this hyopthesis.

For the most value....
If someone you like is priced at below 31/1, bet them to win.
If someone you like is priced above 31/1, bet them E/W.

Makes sense to me. A favourite in the final match loses value when the odds are halved for the E/W, while an underdog gains.

get a job