Math Question Help

[gatso]

This is an absolute nightmare to work out because your odds on the second set depends on the outcome of the first set.

that's what makes it easy to work out, we know set 1 so it's a simple matter of working out the number of permutations

No we don't.

OP gave set 1 as an example. It could actually be any one of 46656 combos.

yeah but we're all answering the example question

love that your last 2 posts were accepting what hopkin wrote and disagreeing with what I wrote when we'd both made the exact same point

[EvilPie]

This is an absolute nightmare to work out because your odds on the second set depends on the outcome of the first set.

that's what makes it easy to work out, we know set 1 so it's a simple matter of working out the number of permutations

No we don't.

OP gave set 1 as an example. It could actually be any one of 46656 combos.

yeah but we're all answering the example question

love that your last 2 posts were accepting what hopkin wrote and disagreeing with what I wrote when we'd both made the exact same point

I wasn't accepting what Hopkin said.

I just couldn't be arsed arguing with Hopkin because all he did was repeat a previous post.

My 'fair enough' was just accepting that he's happy to be wrong.

Your point was easier to counter because you put up an argument against what I'd said which gives me something worth responding to.

[StuartHopkin]

Oh

Im with you now Mattu

We only answered the example 1 1 1 1 2 2

The odds are dependent on what you are trying to match as they obviously change dependent on the permutations available

[StuartHopkin]

Bare with me and its easily sorted, however it is obviously only expressible as a formula

[pleno1]

so the odds of getting 1 1 1 1 2 2 again are?

its 50:50 - obv

[EvilPie]

It's easier if you roll the first set and don't actually look at them.

The odds against getting a match is then 1/6 * 1/6 * 1/6 * 1/6 * 1/6 * 1/6

which is 46656 to 1

Pretty sure that's the answer.

[StuartHopkin]

It's easier if you roll the first set and don't actually look at them.

The odds against getting a match is then 1/6 * 1/6 * 1/6 * 1/6 * 1/6 * 1/6

which is 46656 to 1

Pretty sure that's the answer.

100% wrong as you allow nothing for when dice are duplicated

[EvilPie]

It's easier if you roll the first set and don't actually look at them.

The odds against getting a match is then 1/6 * 1/6 * 1/6 * 1/6 * 1/6 * 1/6

which is 46656 to 1

Pretty sure that's the answer.

100% wrong as you allow nothing for when dice are duplicated

Fair enough.

[kinboshi]

It's easier if you roll the first set and don't actually look at them.

The odds against getting a match is then 1/6 * 1/6 * 1/6 * 1/6 * 1/6 * 1/6

which is 46656 to 1

Pretty sure that's the answer.

100% wrong as you allow nothing for when dice are duplicated

Fair enough.

LOL

[EvilPie]

It's easier if you roll the first set and don't actually look at them.

The odds against getting a match is then 1/6 * 1/6 * 1/6 * 1/6 * 1/6 * 1/6

which is 46656 to 1

Pretty sure that's the answer.

100% wrong as you allow nothing for when dice are duplicated

So are the odds against rolling 1 1 1 1 1 1 different to rolling 1 2 3 4 5 6?

Are the odds different when you roll the whole bunch compared to 1 at a time?

[StuartHopkin]

It's easier if you roll the first set and don't actually look at them.

The odds against getting a match is then 1/6 * 1/6 * 1/6 * 1/6 * 1/6 * 1/6

which is 46656 to 1

Pretty sure that's the answer.

100% wrong as you allow nothing for when dice are duplicated

So are the odds against rolling 1 1 1 1 1 1 different to rolling 1 2 3 4 5 6?

Are the odds different when you roll the whole bunch compared to 1 at a time?

First question would be yes assuming we are not concerned on the order, second question would be no.

[Jon MW]

It's easier if you roll the first set and don't actually look at them.

The odds against getting a match is then 1/6 * 1/6 * 1/6 * 1/6 * 1/6 * 1/6

which is 46656 to 1

Pretty sure that's the answer.

100% wrong as you allow nothing for when dice are duplicated

So are the odds against rolling 1 1 1 1 1 1 different to rolling 1 2 3 4 5 6?

Are the odds different when you roll the whole bunch compared to 1 at a time?

You can roll 123456 and then you can roll 213456 - and they're the same in this scenario as the combination of numbers is what matters not the total number of permutations.

What you said is the same as rolling 123456 followed by 123456 exactly

[EvilPie]

That's why I said don't look at the first set. It's then 46656 to 1 because that's your total combinations.

As soon as you know what the first set is you have other considerations and it gets difficult.

[gatso]

This is an absolute nightmare to work out because your odds on the second set depends on the outcome of the first set.

that's what makes it easy to work out, we know set 1 so it's a simple matter of working out the number of permutations

No we don't.

OP gave set 1 as an example. It could actually be any one of 46656 combos.

yeah but we're all answering the example question

love that your last 2 posts were accepting what hopkin wrote and disagreeing with what I wrote when we'd both made the exact same point

I wasn't accepting what Hopkin said.

I just couldn't be arsed arguing with Hopkin because all he did was repeat a previous post.

My 'fair enough' was just accepting that he's happy to be wrong.

Your point was easier to counter because you put up an argument against what I'd said which gives me something worth responding to.

neil had already cleared up the point you were making and then aciiiid reraised the 111122

1/7776 for 6 same numbers

rolling say 111111 then 111111 again is 1/46656

but if say 1,2,2,4,5,5 then its considerably less as each dice has several chances, bar the last dice.....if u know what i mean. but far to many permutations to work out unless u knew the original 6 dice rolled

ahh thanks! that makes sense.. it was 1 1 1 1 2 2 both times..and i said ball park off the top of my head was 50000/1 friend said 7k

so we were all answering the 111122 weren't we?

it'd help if we were all having the same discussion. that's help a lot of threads actually

[gatso]

That's why I said don't look at the first set. It's then 46656 to 1 because that's your total combinations.

As soon as you know what the first set is you have other considerations and it gets difficult.

norrr, it's only that to throw the exact same numbers in the exact same order. we're throwing 6 dice together

1 in 46656 is only true for 111111, 222222, 333333, 444444, 555555 and 666666 as there's only one possible way of throwing them