Math Question Help

[kinboshi]

I'm confused. 

[EvilPie]

That's why I said don't look at the first set. It's then 46656 to 1 because that's your total combinations.

As soon as you know what the first set is you have other considerations and it gets difficult.

norrr, it's only that to throw the exact same numbers in the exact same order. we're throwing 6 dice together

1 in 46656 is only true for 111111, 222222, 333333, 444444, 555555 and 666666 as there's only one possible way of throwing them

So what are the odds against throwing 111112?

[gatso]

there are 6 ways to throw it so 6 in 46,656

[Simon Galloway]

The difference now is that it doesn't matter if your first roll is a 1 or a 2.  And if it is a 1, it doesn't matter if the 2nd roll is a 1 or a 2.   And so on. Your hopes of still rolling 111112 are kept alive.

[EvilPie]

That's why I said don't look at the first set. It's then 46656 to 1 because that's your total combinations.

As soon as you know what the first set is you have other considerations and it gets difficult.

norrr, it's only that to throw the exact same numbers in the exact same order. we're throwing 6 dice together

1 in 46656 is only true for 111111, 222222, 333333, 444444, 555555 and 666666 as there's only one possible way of throwing them

So what are the odds against throwing 111112?

I'm going to try to answer this myself.

Is it 46656/6 as it could be 111112, 111121, 111211, 112111, 121111 or 211111?

[outragous76]

surely the odds of the first roll are irrelevant as you are setting your target (you obv neednt roll)

therefore the question is what are the odds of rolling any specificc 6 no combo

you then just need to clarify whether order is important, (to which i assume the answer is no)


The above howeve ris very different to the question:

what are the odds of rolling the same 6 numbers twice in a row


.............................

ah fk it

[EvilPie]

Ninja'd

[EvilPie]

That's why I said don't look at the first set. It's then 46656 to 1 because that's your total combinations.

As soon as you know what the first set is you have other considerations and it gets difficult.

norrr, it's only that to throw the exact same numbers in the exact same order. we're throwing 6 dice together

1 in 46656 is only true for 111111, 222222, 333333, 444444, 555555 and 666666 as there's only one possible way of throwing them

So the answer to the OP is that it's impossible to know the odds until you know what the first set of numbers is?

[kinboshi]

That's why I said don't look at the first set. It's then 46656 to 1 because that's your total combinations.

As soon as you know what the first set is you have other considerations and it gets difficult.

norrr, it's only that to throw the exact same numbers in the exact same order. we're throwing 6 dice together

1 in 46656 is only true for 111111, 222222, 333333, 444444, 555555 and 666666 as there's only one possible way of throwing them

So the answer to the OP is that it's impossible to know the odds until you know what the first set of numbers is?

Yes, but he gives an example set - 111122 to work with.  If he'd given 123456 or 333333 the odds would be different.

[gatso]

So the answer to the OP is that it's impossible to know the odds until you know what the first set of numbers is?

nope, there's a definite answer

I think it's 462 in 46,656; 1 in 100.98 so almost exactly 1%

[gatso]

hoping that's right. there are 462 unique sets of numbers that we can make with 6 dice if we ignore the order

[zerofive]

Is this a massive level...?

[smashedagain]

Is this a massive level...?

nope the odds are definatly bigger than massive

[Acidmouse]

lol... i lost the cunting game anyway (its farkle on facebook)

[StuartHopkin]

hoping that's right. there are 462 unique sets of numbers that we can make with 6 dice if we ignore the order

Is this not wrong also as the chance of the first set being certain numbers is higher than other sets of certain numbers?