Here's one for you algebra fans. Spot what goes wrong here as I attempt to prove that one is in fact the same thing as two.
Let a = b
Then you could say that.....
a2 = ab
a2 + a2 = a2 + ab (adding a2 to both sides)
2a2 = a2 + ab
2a2 - 2ab = a2 + ab - 2ab (subtracting 2ab from both sides)
2a2 - 2ab = a2 - ab
which can be written as...
2(a2 - ab) = 1(a2 - ab)
cancelling out the (a2 - ab) leaves us with....
1 = 2
So think twice next time you think you're getting the right pot odds to make a call
Basically you divide through by 0 which is why it's impossible.
Look at it this way....
0 = (A)(0) for any value of A -> 0/0 = A
because if you divide 0 by 0 you can get anything in other words, 0/0 is said to be 'undefined'.
This is what you have what you have:
[(a^2) - ab] / [(a^2) - ab] = 0/0
My name is killjoy, i am here all week