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Author Topic: Vagueness and the Aftermath - A sporadic diary  (Read 4439592 times)
tikay
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« Reply #13455 on: November 08, 2011, 06:45:26 PM »
Quote from: RED-DOG on November 08, 2011, 06:41:02 PM
Yeah, but that's not it.

Told you that you were being argumentative.
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« Reply #13456 on: November 08, 2011, 06:47:00 PM »
Its was probably used as a resting point for shelter in bad weather, and people/animals just caused wear and tear over the years leaning/rubbing on it.
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« Reply #13457 on: November 08, 2011, 06:48:36 PM »
Quote from: outragous76 on November 08, 2011, 06:45:23 PM
duck/swan guano causing detrioration?

Colder...
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« Reply #13458 on: November 08, 2011, 06:49:19 PM »
Quote from: Woodsey on November 08, 2011, 06:47:00 PM
Its was probably used as a resting point for shelter in bad weather, and people/animals just caused wear and tear over the years leaning/rubbing on it.


Colder....






Another clue


 Click to see full-size image.
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technolog
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« Reply #13459 on: November 08, 2011, 06:50:55 PM »
The rope towing the barges?
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« Reply #13460 on: November 08, 2011, 06:51:51 PM »
Quote from: technolog on November 08, 2011, 06:50:55 PM
The rope towing the barges?

I was thinking that but was wondering how?
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« Reply #13461 on: November 08, 2011, 07:00:17 PM »
Quote from: technolog on November 08, 2011, 06:50:55 PM
The rope towing the barges?

Yes! The bridge is on the apex of a bend. and the rope, impregnated with grit, rubs the sandstone away.


They wern't really worried about the damage to the bridge, but the rope used to get trapped and make life difficult for the horses.
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« Reply #13462 on: November 08, 2011, 07:02:22 PM »
Quote from: RED-DOG on November 08, 2011, 01:44:17 PM
Speaking of maths...
                                                                    

...as we were, I learnt something new today.

0.999999999999999 (recurring) = 1
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« Reply #13463 on: November 08, 2011, 07:05:04 PM »
Quote from: technolog on November 08, 2011, 07:02:22 PM
Quote from: RED-DOG on November 08, 2011, 01:44:17 PM
Speaking of maths...
                                                                    

...as we were, I learnt something new today.

0.999999999999999 (recurring) = 1

See now I believe you, but I don't understand it.
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« Reply #13464 on: November 08, 2011, 07:21:02 PM »
OooooOh! So close!

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« Reply #13465 on: November 08, 2011, 07:32:55 PM »
So are they saying that he died because he hit the canopy?


http://www.bbc.co.uk/news/uk-england-15640104
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« Reply #13466 on: November 08, 2011, 07:35:14 PM »
Quote from: RED-DOG on November 08, 2011, 07:05:04 PM
Quote from: technolog on November 08, 2011, 07:02:22 PM
Quote from: RED-DOG on November 08, 2011, 01:44:17 PM
Speaking of maths...
                                                                    

...as we were, I learnt something new today.

0.999999999999999 (recurring) = 1

See now I believe you, but I don't understand it.


I've seen some of the so called proof of this but I'll always believe that  0.99999999 (recurring) will always be less than 1 by an amount that is 0.00000001 (recurring). For every nine you add to the infinite number of recurring  nines, we can add another 0 to the recurring zeros but there will always be an infinitesimal difference  between 0.99999999 (recurring)  and 1.
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« Reply #13467 on: November 08, 2011, 07:39:24 PM »
Quote from: Lucky on November 08, 2011, 07:35:14 PM
Quote from: RED-DOG on November 08, 2011, 07:05:04 PM
Quote from: technolog on November 08, 2011, 07:02:22 PM
Quote from: RED-DOG on November 08, 2011, 01:44:17 PM
Speaking of maths...
                                                                    

...as we were, I learnt something new today.

0.999999999999999 (recurring) = 1

.
See now I believe you, but I don't understand it.


I've seen some of the so called proof of this but I'll always believe that  0.99999999 (recurring) will always be less than 1 by an amount that is 0.00000001 (recurring). For every nine you add to the infinite number of recurring  nines, we can add another 0 to the recurring zeros but there will always be an infinitesimal difference  between 0.99999999 (recurring)  and 1.



Yes. it's like moving halfway to something, stopping and then moving halfway again and so on, you will never get there
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5 2 off


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« Reply #13468 on: November 08, 2011, 07:42:28 PM »
Quote from: Lucky on November 08, 2011, 07:35:14 PM
Quote from: RED-DOG on November 08, 2011, 07:05:04 PM
Quote from: technolog on November 08, 2011, 07:02:22 PM
Quote from: RED-DOG on November 08, 2011, 01:44:17 PM
Speaking of maths...
                                                                    

...as we were, I learnt something new today.

0.999999999999999 (recurring) = 1



See now I believe you, but I don't understand it.


I've seen some of the so called proof of this but I'll always believe that  0.99999999 (recurring) will always be less than 1 by an amount that is 0.00000001 (recurring). For every nine you add to the infinite number of recurring  nines, we can add another 0 to the recurring zeros but there will always be an infinitesimal difference  between 0.99999999 (recurring)  and 1.


yes but 0.99999999 (recurring) +  0.00000001 (recurring) is > than 1
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« Reply #13469 on: November 08, 2011, 07:45:59 PM »
Quote from: 77dave on November 08, 2011, 07:42:28 PM
Quote from: Lucky on November 08, 2011, 07:35:14 PM
Quote from: RED-DOG on November 08, 2011, 07:05:04 PM
Quote from: technolog on November 08, 2011, 07:02:22 PM
Quote from: RED-DOG on November 08, 2011, 01:44:17 PM
Speaking of maths...
                                                                    

...as we were, I learnt something new today.

0.999999999999999 (recurring) = 1



See now I believe you, but I don't understand it.


I've seen some of the so called proof of this but I'll always believe that  0.99999999 (recurring) will always be less than 1 by an amount that is 0.00000001 (recurring). For every nine you add to the infinite number of recurring  nines, we can add another 0 to the recurring zeros but there will always be an infinitesimal difference  between 0.99999999 (recurring)  and 1.


yes but 0.99999999 (recurring) +  0.00000001 (recurring) is > than 1


b=0.9999999999....

10*b = 9.99999999999999....

subtract b from both sides

10*b - b = 9.99999999...... - b

but b=0.999999999........ so that means

9*b = 9

divide both sides by 9

b=1

QED
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